Sum of 1^2 + 2^2 + …. + n^2 series in c programming language
#include<stdio.h>
int main(){
int n,i;
int sum=0;
printf("Enter the n i.e. max values of series: ");
scanf("%d",&n);
sum = (n * (n + 1) * (2 * n + 1 )) / 6;
printf("Sum of the series : ");
for(i =1;i<=n;i++){
if (i != n)
printf("%d^2 + ",i);
else
printf("%d^2 = %d ",i,sum);
}
return 0;
}
Sample output:
Enter the n i.e. max values of series: 5
Sum of the series: 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 55
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